Base | Representation |
---|---|
bin | 10100111100010011… |
… | …10010010101110001 |
3 | 1002000120020211101021 |
4 | 22132021302111301 |
5 | 141011241101314 |
6 | 5055354535441 |
7 | 545422321621 |
oct | 123611622561 |
9 | 32016224337 |
10 | 11243300209 |
11 | 484a605949 |
12 | 2219437581 |
13 | 10a246267b |
14 | 789324881 |
15 | 45c0ed324 |
hex | 29e272571 |
11243300209 has 2 divisors, whose sum is σ = 11243300210. Its totient is φ = 11243300208.
The previous prime is 11243300161. The next prime is 11243300227. The reversal of 11243300209 is 90200334211.
11243300209 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11193640000 + 49660209 = 105800^2 + 7047^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11243300209 is a prime.
It is not a weakly prime, because it can be changed into another prime (11243300279) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621650104 + 5621650105.
It is an arithmetic number, because the mean of its divisors is an integer number (5621650105).
Almost surely, 211243300209 is an apocalyptic number.
It is an amenable number.
11243300209 is a deficient number, since it is larger than the sum of its proper divisors (1).
11243300209 is an equidigital number, since it uses as much as digits as its factorization.
11243300209 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The spelling of 11243300209 in words is "eleven billion, two hundred forty-three million, three hundred thousand, two hundred nine".
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