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112433200241 = 432614725587
BaseRepresentation
bin110100010110110001…
…0100111110001110001
3101202012122220100121112
41220231202213301301
53320230344401431
6123352345403105
711060125301465
oct1505542476161
9352178810545
10112433200241
11437566794aa
1219959799495
13a7aa63b36b
1456284064a5
152dd0a2ac2b
hex1a2d8a7c71

112433200241 has 4 divisors (see below), whose sum is σ = 115047925872. Its totient is φ = 109818474612.

The previous prime is 112433200213. The next prime is 112433200277. The reversal of 112433200241 is 142002334211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112433200241 - 26 = 112433200177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112433206241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1307362751 + ... + 1307362836.

It is an arithmetic number, because the mean of its divisors is an integer number (28761981468).

Almost surely, 2112433200241 is an apocalyptic number.

It is an amenable number.

112433200241 is a deficient number, since it is larger than the sum of its proper divisors (2614725631).

112433200241 is an equidigital number, since it uses as much as digits as its factorization.

112433200241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2614725630.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 112433200241 its reverse (142002334211), we get a palindrome (254435534452).

The spelling of 112433200241 in words is "one hundred twelve billion, four hundred thirty-three million, two hundred thousand, two hundred forty-one".

Divisors: 1 43 2614725587 112433200241