Base | Representation |
---|---|
bin | 1010001110011100101100… |
… | …0000111111110111111111 |
3 | 1110210212000101020022200121 |
4 | 2203213023000333313333 |
5 | 2433202322333400421 |
6 | 35525041134435411 |
7 | 2240206222321432 |
oct | 243471300776777 |
9 | 43725011208617 |
10 | 11243335450111 |
11 | 36452a9826196 |
12 | 131704a362b67 |
13 | 63731b83a6ab |
14 | 2ac274bcb819 |
15 | 1476e936bd41 |
hex | a39cb03fdff |
11243335450111 has 8 divisors (see below), whose sum is σ = 11562371254800. Its totient is φ = 10928582005440.
The previous prime is 11243335450097. The next prime is 11243335450133. The reversal of 11243335450111 is 11105453334211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11243335450111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11243335450511) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1070584680 + ... + 1070595181.
It is an arithmetic number, because the mean of its divisors is an integer number (1445296406850).
Almost surely, 211243335450111 is an apocalyptic number.
11243335450111 is a deficient number, since it is larger than the sum of its proper divisors (319035804689).
11243335450111 is an equidigital number, since it uses as much as digits as its factorization.
11243335450111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2141180009.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 11243335450111 its reverse (11105453334211), we get a palindrome (22348788784322).
The spelling of 11243335450111 in words is "eleven trillion, two hundred forty-three billion, three hundred thirty-five million, four hundred fifty thousand, one hundred eleven".
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