1124342012533 has 2 divisors, whose sum is σ = 1124342012534. Its totient is φ = 1124342012532.

The previous prime is 1124342012501. The next prime is 1124342012603. The reversal of 1124342012533 is 3352102434211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1085145140209 + 39196872324 = 1041703^2 + 197982^2 .

It is a cyclic number.

It is not a de Polignac number, because 1124342012533 - 2⁵ = 1124342012501 is a prime.

It is a super-2 number, since 2×1124342012533² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1124342012495 and 1124342012504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1124342042533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562171006266 + 562171006267.

It is an arithmetic number, because the mean of its divisors is an integer number (562171006267).

Almost surely, 2^{1124342012533} is an apocalyptic number.

It is an amenable number.

1124342012533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124342012533 is an equidigital number, since it uses as much as digits as its factorization.

1124342012533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1124342012533 its reverse (3352102434211), we get a palindrome (4476444446744).

The spelling of 1124342012533 in words is "one trillion, one hundred twenty-four billion, three hundred forty-two million, twelve thousand, five hundred thirty-three".