1124350344433 has 4 divisors (see below), whose sum is σ = 1124355705840. Its totient is φ = 1124344983028.

The previous prime is 1124350344413. The next prime is 1124350344437. The reversal of 1124350344433 is 3344430534211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1124350344433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1124350344392 and 1124350344401.

It is not an unprimeable number, because it can be changed into a prime (1124350344437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2352763 + ... + 2790016.

It is an arithmetic number, because the mean of its divisors is an integer number (281088926460).

Almost surely, 2^{1124350344433} is an apocalyptic number.

It is an amenable number.

1124350344433 is a deficient number, since it is larger than the sum of its proper divisors (5361407).

1124350344433 is an equidigital number, since it uses as much as digits as its factorization.

1124350344433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5361406.

The product of its (nonzero) digits is 207360, while the sum is 37.

Adding to 1124350344433 its reverse (3344430534211), we get a palindrome (4468780878644).

The spelling of 1124350344433 in words is "one trillion, one hundred twenty-four billion, three hundred fifty million, three hundred forty-four thousand, four hundred thirty-three".