Base | Representation |
---|---|
bin | 11001100100001101111010… |
… | …111100001010010000101111 |
3 | 112202010011022201112101201011 |
4 | 121210031322330022100233 |
5 | 104214204120411324012 |
6 | 1035050121140530051 |
7 | 32453344205505046 |
oct | 3144157274122057 |
9 | 482104281471634 |
10 | 112440011433007 |
11 | 329105a5170185 |
12 | 1073b7643b0927 |
13 | 4a980806ca2bb |
14 | 1daa1a889955d |
15 | ceec51acd1a7 |
hex | 66437af0a42f |
112440011433007 has 2 divisors, whose sum is σ = 112440011433008. Its totient is φ = 112440011433006.
The previous prime is 112440011432993. The next prime is 112440011433053. The reversal of 112440011433007 is 700334110044211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112440011433007 - 223 = 112440003044399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112440011433007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112440011433067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56220005716503 + 56220005716504.
It is an arithmetic number, because the mean of its divisors is an integer number (56220005716504).
Almost surely, 2112440011433007 is an apocalyptic number.
112440011433007 is a deficient number, since it is larger than the sum of its proper divisors (1).
112440011433007 is an equidigital number, since it uses as much as digits as its factorization.
112440011433007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 112440011433007 its reverse (700334110044211), we get a palindrome (812774121477218).
The spelling of 112440011433007 in words is "one hundred twelve trillion, four hundred forty billion, eleven million, four hundred thirty-three thousand, seven".
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