Base | Representation |
---|---|
bin | 110100010111000010… |
… | …0001111000111010001 |
3 | 101202020021111001020011 |
4 | 1220232010033013101 |
5 | 3320240123341423 |
6 | 123353302314521 |
7 | 11060263222204 |
oct | 1505604170721 |
9 | 352207431204 |
10 | 112442012113 |
11 | 43760647a42 |
12 | 19960728a41 |
13 | a7ac4051a2 |
14 | 562965b93b |
15 | 2dd16bbb0d |
hex | 1a2e10f1d1 |
112442012113 has 2 divisors, whose sum is σ = 112442012114. Its totient is φ = 112442012112.
The previous prime is 112442012093. The next prime is 112442012143. The reversal of 112442012113 is 311210244211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58212177984 + 54229834129 = 241272^2 + 232873^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112442012113 is a prime.
It is not a weakly prime, because it can be changed into another prime (112442012143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56221006056 + 56221006057.
It is an arithmetic number, because the mean of its divisors is an integer number (56221006057).
Almost surely, 2112442012113 is an apocalyptic number.
It is an amenable number.
112442012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
112442012113 is an equidigital number, since it uses as much as digits as its factorization.
112442012113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 112442012113 its reverse (311210244211), we get a palindrome (423652256324).
The spelling of 112442012113 in words is "one hundred twelve billion, four hundred forty-two million, twelve thousand, one hundred thirteen".
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