Base | Representation |
---|---|
bin | 1101011010010… |
… | …01101101010001 |
3 | 21211200120100112 |
4 | 12231021231101 |
5 | 212244441122 |
6 | 15055131105 |
7 | 2534141663 |
oct | 655115521 |
9 | 254616315 |
10 | 112499537 |
11 | 58559627 |
12 | 31813a95 |
13 | 1a3cbc97 |
14 | 10d26533 |
15 | 9d232e2 |
hex | 6b49b51 |
112499537 has 2 divisors, whose sum is σ = 112499538. Its totient is φ = 112499536.
The previous prime is 112499477. The next prime is 112499539. The reversal of 112499537 is 735994211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112381201 + 118336 = 10601^2 + 344^2 .
It is a cyclic number.
It is not a de Polignac number, because 112499537 - 26 = 112499473 is a prime.
It is a super-2 number, since 2×1124995372 = 25312291650428738, which contains 22 as substring.
Together with 112499539, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 112499494 and 112499503.
It is not a weakly prime, because it can be changed into another prime (112499539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56249768 + 56249769.
It is an arithmetic number, because the mean of its divisors is an integer number (56249769).
Almost surely, 2112499537 is an apocalyptic number.
It is an amenable number.
112499537 is a deficient number, since it is larger than the sum of its proper divisors (1).
112499537 is an equidigital number, since it uses as much as digits as its factorization.
112499537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 68040, while the sum is 41.
The square root of 112499537 is about 10606.5798917464. The cubic root of 112499537 is about 482.7440300477.
The spelling of 112499537 in words is "one hundred twelve million, four hundred ninety-nine thousand, five hundred thirty-seven".
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