Base | Representation |
---|---|
bin | 10100111101000111… |
… | …00010001111010011 |
3 | 1002001000221202100122 |
4 | 22132203202033103 |
5 | 141020003100003 |
6 | 5100155340455 |
7 | 545533563413 |
oct | 123643421723 |
9 | 32030852318 |
10 | 11250050003 |
11 | 48533a6095 |
12 | 221b75172b |
13 | 10a3986a2a |
14 | 78a1a0643 |
15 | 45c9d3238 |
hex | 29e8e23d3 |
11250050003 has 2 divisors, whose sum is σ = 11250050004. Its totient is φ = 11250050002.
The previous prime is 11250049997. The next prime is 11250050047. The reversal of 11250050003 is 30005005211.
It is a weak prime.
It is an emirp because it is prime and its reverse (30005005211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11250050003 - 212 = 11250045907 is a prime.
It is not a weakly prime, because it can be changed into another prime (11250070003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5625025001 + 5625025002.
It is an arithmetic number, because the mean of its divisors is an integer number (5625025002).
Almost surely, 211250050003 is an apocalyptic number.
11250050003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11250050003 is an equidigital number, since it uses as much as digits as its factorization.
11250050003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 17.
Adding to 11250050003 its reverse (30005005211), we get a palindrome (41255055214).
The spelling of 11250050003 in words is "eleven billion, two hundred fifty million, fifty thousand, three".
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