Base | Representation |
---|---|
bin | 10100111101000111… |
… | …01110111101110011 |
3 | 1002001001001101212022 |
4 | 22132203232331303 |
5 | 141020011232011 |
6 | 5100200422055 |
7 | 545534201402 |
oct | 123643567563 |
9 | 32031041768 |
10 | 11250102131 |
11 | 4853431274 |
12 | 221b77792b |
13 | 10a39a4688 |
14 | 78a1b5639 |
15 | 45c9e38db |
hex | 29e8eef73 |
11250102131 has 2 divisors, whose sum is σ = 11250102132. Its totient is φ = 11250102130.
The previous prime is 11250102107. The next prime is 11250102137. The reversal of 11250102131 is 13120105211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11250102131 - 218 = 11249839987 is a prime.
It is a super-2 number, since 2×112501021312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11250102137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5625051065 + 5625051066.
It is an arithmetic number, because the mean of its divisors is an integer number (5625051066).
Almost surely, 211250102131 is an apocalyptic number.
11250102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11250102131 is an equidigital number, since it uses as much as digits as its factorization.
11250102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 11250102131 its reverse (13120105211), we get a palindrome (24370207342).
The spelling of 11250102131 in words is "eleven billion, two hundred fifty million, one hundred two thousand, one hundred thirty-one".
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