Base | Representation |
---|---|
bin | 10000010111101111111… |
… | …101100110001011001111 |
3 | 10222112212001020121112211 |
4 | 100113233331212023033 |
5 | 121413011131203111 |
6 | 2220453515211251 |
7 | 144164566221331 |
oct | 20275775461317 |
9 | 3875761217484 |
10 | 1125012366031 |
11 | 3a412a173884 |
12 | 162050446b27 |
13 | 8211ba51268 |
14 | 3c64534d451 |
15 | 1e3e67b7521 |
hex | 105eff662cf |
1125012366031 has 2 divisors, whose sum is σ = 1125012366032. Its totient is φ = 1125012366030.
The previous prime is 1125012365999. The next prime is 1125012366077. The reversal of 1125012366031 is 1306632105211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1125012366031 - 25 = 1125012365999 is a prime.
It is a super-3 number, since 3×11250123660313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1125012365984 and 1125012366002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1125012363031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562506183015 + 562506183016.
It is an arithmetic number, because the mean of its divisors is an integer number (562506183016).
Almost surely, 21125012366031 is an apocalyptic number.
1125012366031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1125012366031 is an equidigital number, since it uses as much as digits as its factorization.
1125012366031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 1125012366031 in words is "one trillion, one hundred twenty-five billion, twelve million, three hundred sixty-six thousand, thirty-one".
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