Base | Representation |
---|---|
bin | 11001100101010010000001… |
… | …001010010000000110101111 |
3 | 112202101011001111110100122021 |
4 | 121211102001022100012233 |
5 | 104221403342314444122 |
6 | 1035143452442331011 |
7 | 32461543153166566 |
oct | 3145220112200657 |
9 | 482334044410567 |
10 | 112513130234287 |
11 | 32939606895872 |
12 | 1075196b7b9a67 |
13 | 4aa1c340235a3 |
14 | 1dad9437a0bdd |
15 | d01ad0ded1c7 |
hex | 6654812901af |
112513130234287 has 2 divisors, whose sum is σ = 112513130234288. Its totient is φ = 112513130234286.
The previous prime is 112513130234161. The next prime is 112513130234291. The reversal of 112513130234287 is 782432031315211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112513130234287 - 235 = 112478770495919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112513130234987) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56256565117143 + 56256565117144.
It is an arithmetic number, because the mean of its divisors is an integer number (56256565117144).
Almost surely, 2112513130234287 is an apocalyptic number.
112513130234287 is a deficient number, since it is larger than the sum of its proper divisors (1).
112513130234287 is an equidigital number, since it uses as much as digits as its factorization.
112513130234287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 43.
Adding to 112513130234287 its reverse (782432031315211), we get a palindrome (894945161549498).
The spelling of 112513130234287 in words is "one hundred twelve trillion, five hundred thirteen billion, one hundred thirty million, two hundred thirty-four thousand, two hundred eighty-seven".
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