Base | Representation |
---|---|
bin | 1010001110111101101110… |
… | …1101100110111001110001 |
3 | 1110211200220112211021100110 |
4 | 2203233123231212321301 |
5 | 2433324004102424403 |
6 | 35533105235011533 |
7 | 2240642066530146 |
oct | 243573355467161 |
9 | 43750815737313 |
10 | 11252205514353 |
11 | 36490407397a1 |
12 | 1318904a39ba9 |
13 | 6381033c550b |
14 | 2ac876c5c3cd |
15 | 147a67e2e103 |
hex | a3bdbb66e71 |
11252205514353 has 12 divisors (see below), whose sum is σ = 15683603403440. Its totient is φ = 7175319457416.
The previous prime is 11252205514351. The next prime is 11252205514367. The reversal of 11252205514353 is 35341550225211.
It is not a de Polignac number, because 11252205514353 - 21 = 11252205514351 is a prime.
It is a super-2 number, since 2×112522055143532 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11252205514351) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3545116723 + ... + 3545119896.
Almost surely, 211252205514353 is an apocalyptic number.
It is an amenable number.
11252205514353 is a deficient number, since it is larger than the sum of its proper divisors (4431397889087).
11252205514353 is an equidigital number, since it uses as much as digits as its factorization.
11252205514353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7090236668 (or 7090236645 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 11252205514353 its reverse (35341550225211), we get a palindrome (46593755739564).
The spelling of 11252205514353 in words is "eleven trillion, two hundred fifty-two billion, two hundred five million, five hundred fourteen thousand, three hundred fifty-three".
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