Base | Representation |
---|---|
bin | 10100111101011101… |
… | …10010011111000011 |
3 | 1002001020111122011122 |
4 | 22132232302133003 |
5 | 141021232001011 |
6 | 5100342502455 |
7 | 545600631362 |
oct | 123656623703 |
9 | 32036448148 |
10 | 11253000131 |
11 | 485503060a |
12 | 2220734a2b |
13 | 10a447a779 |
14 | 78a72b7d9 |
15 | 45cdb73db |
hex | 29ebb27c3 |
11253000131 has 2 divisors, whose sum is σ = 11253000132. Its totient is φ = 11253000130.
The previous prime is 11253000127. The next prime is 11253000223. The reversal of 11253000131 is 13100035211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11253000131 - 22 = 11253000127 is a prime.
It is a super-2 number, since 2×112530001312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11253000431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5626500065 + 5626500066.
It is an arithmetic number, because the mean of its divisors is an integer number (5626500066).
Almost surely, 211253000131 is an apocalyptic number.
11253000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11253000131 is an equidigital number, since it uses as much as digits as its factorization.
11253000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 11253000131 its reverse (13100035211), we get a palindrome (24353035342).
The spelling of 11253000131 in words is "eleven billion, two hundred fifty-three million, one hundred thirty-one", and thus it is an aban number.
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