Base | Representation |
---|---|
bin | 10000011000000010011… |
… | …110110000111000111011 |
3 | 10222120122200212000121001 |
4 | 100120002132300320323 |
5 | 121414130200104210 |
6 | 2220544414225431 |
7 | 144205361051164 |
oct | 20300236607073 |
9 | 3876580760531 |
10 | 1125323050555 |
11 | 3a4279585750 |
12 | 1621184b5277 |
13 | 8216b220362 |
14 | 3c67470476b |
15 | 1e413bd703a |
hex | 106027b0e3b |
1125323050555 has 32 divisors (see below), whose sum is σ = 1484027308800. Its totient is φ = 812381258880.
The previous prime is 1125323050549. The next prime is 1125323050559. The reversal of 1125323050555 is 5550503235211.
It is not a de Polignac number, because 1125323050555 - 215 = 1125323017787 is a prime.
It is a super-2 number, since 2×11253230505552 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1125323050559) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12435904 + ... + 12526066.
It is an arithmetic number, because the mean of its divisors is an integer number (46375853400).
Almost surely, 21125323050555 is an apocalyptic number.
1125323050555 is a deficient number, since it is larger than the sum of its proper divisors (358704258245).
1125323050555 is a wasteful number, since it uses less digits than its factorization.
1125323050555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91851.
The product of its (nonzero) digits is 112500, while the sum is 37.
Adding to 1125323050555 its reverse (5550503235211), we get a palindrome (6675826285766).
The spelling of 1125323050555 in words is "one trillion, one hundred twenty-five billion, three hundred twenty-three million, fifty thousand, five hundred fifty-five".
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