112541131 has 2 divisors, whose sum is σ = 112541132. Its totient is φ = 112541130.

The previous prime is 112541089. The next prime is 112541137. The reversal of 112541131 is 131145211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112541131 - 2¹⁹ = 112016843 is a prime.

It is a super-2 number, since 2×112541131² = 25331012333518322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112541099 and 112541108.

It is not a weakly prime, because it can be changed into another prime (112541137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56270565 + 56270566.

It is an arithmetic number, because the mean of its divisors is an integer number (56270566).

Almost surely, 2^112541131 is an apocalyptic number.

112541131 is a deficient number, since it is larger than the sum of its proper divisors (1).

112541131 is an equidigital number, since it uses as much as digits as its factorization.

112541131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 19.

The square root of 112541131 is about 10608.5404745422. The cubic root of 112541131 is about 482.8035170513.

Adding to 112541131 its reverse (131145211), we get a palindrome (243686342).

The spelling of 112541131 in words is "one hundred twelve million, five hundred forty-one thousand, one hundred thirty-one".