Base | Representation |
---|---|
bin | 10100111101101100… |
… | …00101010001110101 |
3 | 1002001101002202220221 |
4 | 22132312011101311 |
5 | 141022224141432 |
6 | 5100451454341 |
7 | 545623113601 |
oct | 123666052165 |
9 | 32041082827 |
10 | 11254912117 |
11 | 4856117069 |
12 | 22212b73b1 |
13 | 10a4999b17 |
14 | 78aaa8501 |
15 | 45d143b97 |
hex | 29ed85475 |
11254912117 has 2 divisors, whose sum is σ = 11254912118. Its totient is φ = 11254912116.
The previous prime is 11254912099. The next prime is 11254912129. The reversal of 11254912117 is 71121945211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9402986961 + 1851925156 = 96969^2 + 43034^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11254912117 is a prime.
It is a super-2 number, since 2×112549121172 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11254912187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627456058 + 5627456059.
It is an arithmetic number, because the mean of its divisors is an integer number (5627456059).
Almost surely, 211254912117 is an apocalyptic number.
It is an amenable number.
11254912117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11254912117 is an equidigital number, since it uses as much as digits as its factorization.
11254912117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5040, while the sum is 34.
The spelling of 11254912117 in words is "eleven billion, two hundred fifty-four million, nine hundred twelve thousand, one hundred seventeen".
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