11255434151 has 32 divisors (see below), whose sum is σ = 13294041600. Its totient is φ = 9445040640.

The previous prime is 11255434133. The next prime is 11255434153. The reversal of 11255434151 is 15143455211.

It is a cyclic number.

It is not a de Polignac number, because 11255434151 - 2¹⁸ = 11255172007 is a prime.

It is a super-3 number, since 3×11255434151³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11255434153) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 419405 + ... + 445433.

It is an arithmetic number, because the mean of its divisors is an integer number (415438800).

Almost surely, 2^11255434151 is an apocalyptic number.

11255434151 is a deficient number, since it is larger than the sum of its proper divisors (2038607449).

11255434151 is a wasteful number, since it uses less digits than its factorization.

11255434151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26139.

The product of its digits is 12000, while the sum is 32.

Adding to 11255434151 its reverse (15143455211), we get a palindrome (26398889362).

The spelling of 11255434151 in words is "eleven billion, two hundred fifty-five million, four hundred thirty-four thousand, one hundred fifty-one".