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11255525430151 = 18162185223371
BaseRepresentation
bin1010001111001010000110…
…0110000101001110000111
31110212000110220211110122211
42203302201212011032013
52433402304002231101
635534414512204251
72241120261411022
oct243624146051607
943760426743584
1011255525430151
11364a494746662
121319490839687
1363851215b832
142acaadb401b9
15147bae617c51
hexa3ca1985387

11255525430151 has 4 divisors (see below), whose sum is σ = 11317710653704. Its totient is φ = 11193340206600.

The previous prime is 11255525430119. The next prime is 11255525430157. The reversal of 11255525430151 is 15103452555211.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11255525430151 - 25 = 11255525430119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11255525430157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31092611505 + ... + 31092611866.

It is an arithmetic number, because the mean of its divisors is an integer number (2829427663426).

Almost surely, 211255525430151 is an apocalyptic number.

11255525430151 is a deficient number, since it is larger than the sum of its proper divisors (62185223553).

11255525430151 is an equidigital number, since it uses as much as digits as its factorization.

11255525430151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62185223552.

The product of its (nonzero) digits is 150000, while the sum is 40.

Adding to 11255525430151 its reverse (15103452555211), we get a palindrome (26358977985362).

The spelling of 11255525430151 in words is "eleven trillion, two hundred fifty-five billion, five hundred twenty-five million, four hundred thirty thousand, one hundred fifty-one".

Divisors: 1 181 62185223371 11255525430151