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112562534113 is a prime number
BaseRepresentation
bin110100011010100111…
…1111111011011100001
3101202112200021012022221
41220311033333123201
53321012002042423
6123413245431041
711063255516251
oct1506517773341
9352480235287
10112562534113
11438126859a7
1219994b6b481
13a7cb382893
14563b671961
152ddc076e5d
hex1a353ff6e1

112562534113 has 2 divisors, whose sum is σ = 112562534114. Its totient is φ = 112562534112.

The previous prime is 112562534089. The next prime is 112562534177. The reversal of 112562534113 is 311435265211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112525360704 + 37173409 = 335448^2 + 6097^2 .

It is a cyclic number.

It is not a de Polignac number, because 112562534113 - 213 = 112562525921 is a prime.

It is a super-3 number, since 3×1125625341133 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (112562534713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56281267056 + 56281267057.

It is an arithmetic number, because the mean of its divisors is an integer number (56281267057).

Almost surely, 2112562534113 is an apocalyptic number.

It is an amenable number.

112562534113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112562534113 is an equidigital number, since it uses as much as digits as its factorization.

112562534113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 34.

Adding to 112562534113 its reverse (311435265211), we get a palindrome (423997799324).

The spelling of 112562534113 in words is "one hundred twelve billion, five hundred sixty-two million, five hundred thirty-four thousand, one hundred thirteen".