Base | Representation |
---|---|
bin | 1010001111101111000011… |
… | …0010011101110000101101 |
3 | 1110212222002011101120210001 |
4 | 2203323300302131300231 |
5 | 2434033112131323203 |
6 | 35543135025544301 |
7 | 2241621130066351 |
oct | 243736062356055 |
9 | 43788064346701 |
10 | 11265444011053 |
11 | 3653714500261 |
12 | 131b39a4a5091 |
13 | 63943300ca0b |
14 | 2ad37114b461 |
15 | 14809029191d |
hex | a3ef0c9dc2d |
11265444011053 has 2 divisors, whose sum is σ = 11265444011054. Its totient is φ = 11265444011052.
The previous prime is 11265444010973. The next prime is 11265444011071. The reversal of 11265444011053 is 35011044456211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7299280151524 + 3966163859529 = 2701718^2 + 1991523^2 .
It is a cyclic number.
It is not a de Polignac number, because 11265444011053 - 213 = 11265444002861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11265444011953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5632722005526 + 5632722005527.
It is an arithmetic number, because the mean of its divisors is an integer number (5632722005527).
Almost surely, 211265444011053 is an apocalyptic number.
It is an amenable number.
11265444011053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11265444011053 is an equidigital number, since it uses as much as digits as its factorization.
11265444011053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 11265444011053 its reverse (35011044456211), we get a palindrome (46276488467264).
The spelling of 11265444011053 in words is "eleven trillion, two hundred sixty-five billion, four hundred forty-four million, eleven thousand, fifty-three".
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