Base | Representation |
---|---|
bin | 11001100111100000100111… |
… | …011010001111110011001011 |
3 | 112202220210021012201000121111 |
4 | 121213200213122033303023 |
5 | 104231410431241104210 |
6 | 1035342054014551151 |
7 | 32505603352606030 |
oct | 3147404732176313 |
9 | 482823235630544 |
10 | 112666243300555 |
11 | 3299853815a75a |
12 | 10777580b084b7 |
13 | 4ab34c5524199 |
14 | 1db710a78b387 |
15 | d05a92e5788a |
hex | 66782768fccb |
112666243300555 has 64 divisors (see below), whose sum is σ = 156613331976192. Its totient is φ = 76213399582080.
The previous prime is 112666243300553. The next prime is 112666243300579. The reversal of 112666243300555 is 555003342666211.
It is not a de Polignac number, because 112666243300555 - 21 = 112666243300553 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112666243300499 and 112666243300508.
It is not an unprimeable number, because it can be changed into a prime (112666243300553) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2057164782 + ... + 2057219548.
It is an arithmetic number, because the mean of its divisors is an integer number (2447083312128).
Almost surely, 2112666243300555 is an apocalyptic number.
112666243300555 is a deficient number, since it is larger than the sum of its proper divisors (43947088675637).
112666243300555 is a wasteful number, since it uses less digits than its factorization.
112666243300555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57184.
The product of its (nonzero) digits is 3888000, while the sum is 49.
Adding to 112666243300555 its reverse (555003342666211), we get a palindrome (667669585966766).
The spelling of 112666243300555 in words is "one hundred twelve trillion, six hundred sixty-six billion, two hundred forty-three million, three hundred thousand, five hundred fifty-five".
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