Base | Representation |
---|---|
bin | 11001100111100100001111… |
… | …010101010101000011011111 |
3 | 112202221011022101100120100102 |
4 | 121213210033111111003133 |
5 | 104231441413341403341 |
6 | 1035343540053051315 |
7 | 32506101651020012 |
oct | 3147441725250337 |
9 | 482834271316312 |
10 | 112670134325471 |
11 | 3299a154582328 |
12 | 10778288026b3b |
13 | 4ab39956abba8 |
14 | 1db7399455379 |
15 | d05c1e853c9b |
hex | 66790f5550df |
112670134325471 has 4 divisors (see below), whose sum is σ = 112695958334952. Its totient is φ = 112644310315992.
The previous prime is 112670134325467. The next prime is 112670134325513. The reversal of 112670134325471 is 174523431076211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 112670134325471 - 22 = 112670134325467 is a prime.
It is a super-3 number, since 3×1126701343254713 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112670134325431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12911998196 + ... + 12912006921.
It is an arithmetic number, because the mean of its divisors is an integer number (28173989583738).
Almost surely, 2112670134325471 is an apocalyptic number.
112670134325471 is a deficient number, since it is larger than the sum of its proper divisors (25824009481).
112670134325471 is an equidigital number, since it uses as much as digits as its factorization.
112670134325471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25824009480.
The product of its (nonzero) digits is 846720, while the sum is 47.
The spelling of 112670134325471 in words is "one hundred twelve trillion, six hundred seventy billion, one hundred thirty-four million, three hundred twenty-five thousand, four hundred seventy-one".
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