Base | Representation |
---|---|
bin | 110100100001000001… |
… | …1100000100010001001 |
3 | 101210002122111202210012 |
4 | 1221002003200202021 |
5 | 3321432001200031 |
6 | 123450442201305 |
7 | 11101504535243 |
oct | 1510203404211 |
9 | 353078452705 |
10 | 112777365641 |
11 | 43912979016 |
12 | 19a34ab3235 |
13 | a833a30925 |
14 | 565bdd5093 |
15 | 2e00d60b2b |
hex | 1a420e0889 |
112777365641 has 2 divisors, whose sum is σ = 112777365642. Its totient is φ = 112777365640.
The previous prime is 112777365593. The next prime is 112777365643. The reversal of 112777365641 is 146563777211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73799155600 + 38978210041 = 271660^2 + 197429^2 .
It is a cyclic number.
It is not a de Polignac number, because 112777365641 - 218 = 112777103497 is a prime.
Together with 112777365643, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112777365641.
It is not a weakly prime, because it can be changed into another prime (112777365643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56388682820 + 56388682821.
It is an arithmetic number, because the mean of its divisors is an integer number (56388682821).
Almost surely, 2112777365641 is an apocalyptic number.
It is an amenable number.
112777365641 is a deficient number, since it is larger than the sum of its proper divisors (1).
112777365641 is an equidigital number, since it uses as much as digits as its factorization.
112777365641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1481760, while the sum is 50.
The spelling of 112777365641 in words is "one hundred twelve billion, seven hundred seventy-seven million, three hundred sixty-five thousand, six hundred forty-one".
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