Base | Representation |
---|---|
bin | 10101000001000111… |
… | …01000000011010011 |
3 | 1002010101010201001011 |
4 | 22200203220003103 |
5 | 141102102100433 |
6 | 5103355151351 |
7 | 546422154226 |
oct | 124043500323 |
9 | 32111121034 |
10 | 11283628243 |
11 | 487034a9a8 |
12 | 222aa45557 |
13 | 10aa912604 |
14 | 7908215bd |
15 | 4609173cd |
hex | 2a08e80d3 |
11283628243 has 2 divisors, whose sum is σ = 11283628244. Its totient is φ = 11283628242.
The previous prime is 11283628207. The next prime is 11283628247. The reversal of 11283628243 is 34282638211.
It is a strong prime.
It is an emirp because it is prime and its reverse (34282638211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11283628243 - 29 = 11283627731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11283628196 and 11283628205.
It is not a weakly prime, because it can be changed into another prime (11283628247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5641814121 + 5641814122.
It is an arithmetic number, because the mean of its divisors is an integer number (5641814122).
Almost surely, 211283628243 is an apocalyptic number.
11283628243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11283628243 is an equidigital number, since it uses as much as digits as its factorization.
11283628243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 40.
The spelling of 11283628243 in words is "eleven billion, two hundred eighty-three million, six hundred twenty-eight thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •