Base | Representation |
---|---|
bin | 110100100010111101… |
… | …1000000100100101011 |
3 | 101210021011121001111212 |
4 | 1221011323000210223 |
5 | 3322100103341233 |
6 | 123501120543335 |
7 | 11103223161143 |
oct | 1510573004453 |
9 | 353234531455 |
10 | 112842246443 |
11 | 43946562a13 |
12 | 19a52781b4b |
13 | a8442c9334 |
14 | 5666883923 |
15 | 2e068c9a48 |
hex | 1a45ec092b |
112842246443 has 2 divisors, whose sum is σ = 112842246444. Its totient is φ = 112842246442.
The previous prime is 112842246397. The next prime is 112842246499. The reversal of 112842246443 is 344642248211.
It is a weak prime.
It is an emirp because it is prime and its reverse (344642248211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112842246443 - 26 = 112842246379 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112842246443.
It is not a weakly prime, because it can be changed into another prime (112842236443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56421123221 + 56421123222.
It is an arithmetic number, because the mean of its divisors is an integer number (56421123222).
Almost surely, 2112842246443 is an apocalyptic number.
112842246443 is a deficient number, since it is larger than the sum of its proper divisors (1).
112842246443 is an equidigital number, since it uses as much as digits as its factorization.
112842246443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 294912, while the sum is 41.
The spelling of 112842246443 in words is "one hundred twelve billion, eight hundred forty-two million, two hundred forty-six thousand, four hundred forty-three".
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