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11300022555335 = 5172110487125221
BaseRepresentation
bin1010010001101111110111…
…0101001001001011000111
31111000021100000000122011022
42210123331311021023013
52440114421233232320
640011054140101355
72244254043626663
oct244337565111307
944007300018138
1011300022555335
113667349161388
12132602a83485b
1363c783b1c1c7
142b0cd16a98a3
15148e15d21325
hexa46fdd492c7

11300022555335 has 16 divisors (see below), whose sum is σ = 13569308367552. Its totient is φ = 9033831609600.

The previous prime is 11300022555281. The next prime is 11300022555347. The reversal of 11300022555335 is 53355522000311.

It is not a de Polignac number, because 11300022555335 - 26 = 11300022555271 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11300022555295 and 11300022555304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 90178025 + ... + 90303245.

It is an arithmetic number, because the mean of its divisors is an integer number (848081772972).

Almost surely, 211300022555335 is an apocalyptic number.

11300022555335 is a deficient number, since it is larger than the sum of its proper divisors (2269285812217).

11300022555335 is a wasteful number, since it uses less digits than its factorization.

11300022555335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137434.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 11300022555335 its reverse (53355522000311), we get a palindrome (64655544555646).

The spelling of 11300022555335 in words is "eleven trillion, three hundred billion, twenty-two million, five hundred fifty-five thousand, three hundred thirty-five".

Divisors: 1 5 1721 8605 10487 52435 125221 626105 18048127 90240635 215505341 1077526705 1313192627 6565963135 2260004511067 11300022555335