1130003004113 has 4 divisors (see below), whose sum is σ = 1130005133040. Its totient is φ = 1130000875188.

The previous prime is 1130003004101. The next prime is 1130003004211. The reversal of 1130003004113 is 3114003000311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1130003004113 - 2¹⁶ = 1130002938577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130003004091 and 1130003004100.

It is not an unprimeable number, because it can be changed into a prime (1130003004313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 449006 + ... + 1568952.

It is an arithmetic number, because the mean of its divisors is an integer number (282501283260).

Almost surely, 2^{1130003004113} is an apocalyptic number.

It is an amenable number.

1130003004113 is a deficient number, since it is larger than the sum of its proper divisors (2128927).

1130003004113 is a wasteful number, since it uses less digits than its factorization.

1130003004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2128926.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1130003004113 its reverse (3114003000311), we get a palindrome (4244006004424).

It can be divided in two parts, 113000 and 3004113, that added together give a palindrome (3117113).

The spelling of 1130003004113 in words is "one trillion, one hundred thirty billion, three million, four thousand, one hundred thirteen".