Base | Representation |
---|---|
bin | 1010010001101111111001… |
… | …0010101110011001111101 |
3 | 1111000021100112121121120121 |
4 | 2210123332102232121331 |
5 | 2440114430224410023 |
6 | 40011055014214541 |
7 | 2244254166555244 |
oct | 244337622563175 |
9 | 44007315547517 |
10 | 11300030310013 |
11 | 3667352578605 |
12 | 1326031354451 |
13 | 63c785605a83 |
14 | 2b0cd272795b |
15 | 148e16853d5d |
hex | a46fe4ae67d |
11300030310013 has 2 divisors, whose sum is σ = 11300030310014. Its totient is φ = 11300030310012.
The previous prime is 11300030310001. The next prime is 11300030310053. The reversal of 11300030310013 is 31001303000311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10736717016249 + 563313293764 = 3276693^2 + 750542^2 .
It is a cyclic number.
It is not a de Polignac number, because 11300030310013 - 225 = 11299996755581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300030310053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650015155006 + 5650015155007.
It is an arithmetic number, because the mean of its divisors is an integer number (5650015155007).
Almost surely, 211300030310013 is an apocalyptic number.
It is an amenable number.
11300030310013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300030310013 is an equidigital number, since it uses as much as digits as its factorization.
11300030310013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 11300030310013 its reverse (31001303000311), we get a palindrome (42301333310324).
The spelling of 11300030310013 in words is "eleven trillion, three hundred billion, thirty million, three hundred ten thousand, thirteen".
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