Base | Representation |
---|---|
bin | 10000011100011001011… |
… | …111111011101100010011 |
3 | 11000000201221021001201020 |
4 | 100130121133323230103 |
5 | 122003222033401321 |
6 | 2223041115410523 |
7 | 144432362135625 |
oct | 20343137735423 |
9 | 4000657231636 |
10 | 1130004200211 |
11 | 3a6260a03777 |
12 | 163004153a43 |
13 | 82735cb10b3 |
14 | 3c99a2c6c15 |
15 | 1e5d9b594c6 |
hex | 107197fbb13 |
1130004200211 has 4 divisors (see below), whose sum is σ = 1506672266952. Its totient is φ = 753336133472.
The previous prime is 1130004200209. The next prime is 1130004200249. The reversal of 1130004200211 is 1120024000311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1130004200211 - 21 = 1130004200209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1130004201211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188334033366 + ... + 188334033371.
It is an arithmetic number, because the mean of its divisors is an integer number (376668066738).
Almost surely, 21130004200211 is an apocalyptic number.
1130004200211 is a deficient number, since it is larger than the sum of its proper divisors (376668066741).
1130004200211 is an equidigital number, since it uses as much as digits as its factorization.
1130004200211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 376668066740.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 1130004200211 its reverse (1120024000311), we get a palindrome (2250028200522).
The spelling of 1130004200211 in words is "one trillion, one hundred thirty billion, four million, two hundred thousand, two hundred eleven".
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