Base | Representation |
---|---|
bin | 1010010001110000001100… |
… | …0011110111101101010001 |
3 | 1111000021120010010122000000 |
4 | 2210130003003313231101 |
5 | 2440120111214131113 |
6 | 40011110552520213 |
7 | 2244256160516160 |
oct | 244340303675521 |
9 | 44007503118000 |
10 | 11300110302033 |
11 | 3667393743813 |
12 | 13260540b0069 |
13 | 63c799062627 |
14 | 2b0cdd1cb3d7 |
15 | 148e1d8a5373 |
hex | a47030f7b51 |
11300110302033 has 112 divisors (see below), whose sum is σ = 19455037508736. Its totient is φ = 6426487952640.
The previous prime is 11300110302029. The next prime is 11300110302109. The reversal of 11300110302033 is 33020301100311.
It is a happy number.
It is not a de Polignac number, because 11300110302033 - 22 = 11300110302029 is a prime.
It is a super-2 number, since 2×113001103020332 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11300110301997 and 11300110302015.
It is not an unprimeable number, because it can be changed into a prime (11300110302433) by changing a digit.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 1372534485 + ... + 1372542717.
Almost surely, 211300110302033 is an apocalyptic number.
It is an amenable number.
11300110302033 is a deficient number, since it is larger than the sum of its proper divisors (8154927206703).
11300110302033 is an frugal number, since it uses more digits than its factorization.
11300110302033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9506 (or 9491 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 11300110302033 its reverse (33020301100311), we get a palindrome (44320411402344).
The spelling of 11300110302033 in words is "eleven trillion, three hundred billion, one hundred ten million, three hundred two thousand, thirty-three".
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