Base | Representation |
---|---|
bin | 10101000011000101… |
… | …00000001111001011 |
3 | 1002011112011010120000 |
4 | 22201202200033023 |
5 | 141120312030212 |
6 | 5105144334043 |
7 | 550012234632 |
oct | 124142401713 |
9 | 32145133500 |
10 | 11300111307 |
11 | 4879688971 |
12 | 2234474323 |
13 | 10b1163cc4 |
14 | 792ab2519 |
15 | 4620c11dc |
hex | 2a18a03cb |
11300111307 has 10 divisors (see below), whose sum is σ = 16880413308. Its totient is φ = 7533407484.
The previous prime is 11300111299. The next prime is 11300111323. The reversal of 11300111307 is 70311100311.
It is not a de Polignac number, because 11300111307 - 23 = 11300111299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11300111307.
It is not an unprimeable number, because it can be changed into a prime (11300111387) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 69753693 + ... + 69753854.
Almost surely, 211300111307 is an apocalyptic number.
11300111307 is a deficient number, since it is larger than the sum of its proper divisors (5580302001).
11300111307 is an equidigital number, since it uses as much as digits as its factorization.
11300111307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139507559 (or 139507550 counting only the distinct ones).
The product of its (nonzero) digits is 63, while the sum is 18.
Adding to 11300111307 its reverse (70311100311), we get a palindrome (81611211618).
The spelling of 11300111307 in words is "eleven billion, three hundred million, one hundred eleven thousand, three hundred seven".
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