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113001222133 = 200235643571
BaseRepresentation
bin110100100111101100…
…1011100111111110101
3101210200020201212011101
41221033121130333311
53322411303102013
6123525000210101
711110163353132
oct1511731347765
9353606655141
10113001222133
1143a18275788
1219a97a69931
13a86b21b7a7
14567da27589
152e1582d8dd
hex1a4f65cff5

113001222133 has 4 divisors (see below), whose sum is σ = 113006885728. Its totient is φ = 112995558540.

The previous prime is 113001222107. The next prime is 113001222149. The reversal of 113001222133 is 331222100311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113001222133 - 217 = 113001091061 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113001222133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113001222163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2801763 + ... + 2841808.

It is an arithmetic number, because the mean of its divisors is an integer number (28251721432).

Almost surely, 2113001222133 is an apocalyptic number.

It is an amenable number.

113001222133 is a deficient number, since it is larger than the sum of its proper divisors (5663595).

113001222133 is an equidigital number, since it uses as much as digits as its factorization.

113001222133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5663594.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 113001222133 its reverse (331222100311), we get a palindrome (444223322444).

The spelling of 113001222133 in words is "one hundred thirteen billion, one million, two hundred twenty-two thousand, one hundred thirty-three".

Divisors: 1 20023 5643571 113001222133