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1130013005434 = 28292381328621
BaseRepresentation
bin10000011100011010000…
…001100001011001111010
311000000202112211102012121
4100130122001201121322
5122003231312133214
62223042032231454
7144432530031055
oct20343201413172
94000675742177
101130013005434
113a6265978215
1216300709b58a
1382737a74ba1
143c99b539a9c
151e5da7e8424
hex1071a06167a

1130013005434 has 16 divisors (see below), whose sum is σ = 1697194726920. Its totient is φ = 564281536320.

The previous prime is 1130013005431. The next prime is 1130013005453. The reversal of 1130013005434 is 4345003100311.

It can be written as a sum of positive squares in 4 ways, for example, as 667676923225 + 462336082209 = 817115^2 + 679953^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1130013005399 and 1130013005408.

It is not an unprimeable number, because it can be changed into a prime (1130013005431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39467644 + ... + 39496264.

Almost surely, 21130013005434 is an apocalyptic number.

1130013005434 is a deficient number, since it is larger than the sum of its proper divisors (567181721486).

1130013005434 is a wasteful number, since it uses less digits than its factorization.

1130013005434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53265.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1130013005434 its reverse (4345003100311), we get a palindrome (5475016105745).

The spelling of 1130013005434 in words is "one trillion, one hundred thirty billion, thirteen million, five thousand, four hundred thirty-four".

Divisors: 1 2 829 1658 23813 28621 47626 57242 19740977 23726809 39481954 47453618 681551873 1363103746 565006502717 1130013005434