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113001310303 = 729556656701
BaseRepresentation
bin110100100111101100…
…1110010100001011111
3101210200020220100002221
41221033121302201133
53322411313412203
6123525002130211
711110164201160
oct1511731624137
9353606810087
10113001310303
1143a18325a52
1219a97ab0967
13a86b24c96b
14567da4b767
152e15849abd
hex1a4f67285f

113001310303 has 8 divisors (see below), whose sum is σ = 133597608480. Its totient is φ = 93518325600.

The previous prime is 113001310273. The next prime is 113001310309. The reversal of 113001310303 is 303013100311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113001310303 - 233 = 104411375711 is a prime.

It is a super-2 number, since 2×1130013103032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113001310309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 278328148 + ... + 278328553.

It is an arithmetic number, because the mean of its divisors is an integer number (16699701060).

Almost surely, 2113001310303 is an apocalyptic number.

113001310303 is a deficient number, since it is larger than the sum of its proper divisors (20596298177).

113001310303 is an equidigital number, since it uses as much as digits as its factorization.

113001310303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556656737.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 113001310303 its reverse (303013100311), we get a palindrome (416014410614).

The spelling of 113001310303 in words is "one hundred thirteen billion, one million, three hundred ten thousand, three hundred three".

Divisors: 1 7 29 203 556656701 3896596907 16143044329 113001310303