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11300143433 = 61197993607
BaseRepresentation
bin10101000011000101…
…01000000101001001
31002011112012202121212
422201202220011021
5141120314042213
65105145142505
7550012430405
oct124142500511
932145182555
1011300143433
114879700017
12223448aa35
1310b1175807
14792ac0105
154620ca9a8
hex2a18a8149

11300143433 has 8 divisors (see below), whose sum is σ = 11491318080. Its totient is φ = 11109160080.

The previous prime is 11300143427. The next prime is 11300143483. The reversal of 11300143433 is 33434100311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11300143433 - 24 = 11300143417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11300143399 and 11300143408.

It is not an unprimeable number, because it can be changed into a prime (11300143403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73916 + ... + 167522.

It is an arithmetic number, because the mean of its divisors is an integer number (1436414760).

Almost surely, 211300143433 is an apocalyptic number.

It is an amenable number.

11300143433 is a deficient number, since it is larger than the sum of its proper divisors (191174647).

11300143433 is an equidigital number, since it uses as much as digits as its factorization.

11300143433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95647.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11300143433 its reverse (33434100311), we get a palindrome (44734243744).

The spelling of 11300143433 in words is "eleven billion, three hundred million, one hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 61 1979 93607 120719 5710027 185248253 11300143433