1130021000131 has 4 divisors (see below), whose sum is σ = 1130063140072. Its totient is φ = 1129978860192.

The previous prime is 1130021000117. The next prime is 1130021000161. The reversal of 1130021000131 is 1310001200311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130021000131 is a prime.

It is a super-2 number, since 2×1130021000131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130021000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21029721 + ... + 21083386.

It is an arithmetic number, because the mean of its divisors is an integer number (282515785018).

Almost surely, 2^{1130021000131} is an apocalyptic number.

1130021000131 is a deficient number, since it is larger than the sum of its proper divisors (42139941).

1130021000131 is an equidigital number, since it uses as much as digits as its factorization.

1130021000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42139940.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1130021000131 its reverse (1310001200311), we get a palindrome (2440022200442).

The spelling of 1130021000131 in words is "one trillion, one hundred thirty billion, twenty-one million, one hundred thirty-one", and thus it is an aban number.