Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11000010101010011 |
3 | 1002011112100010221102 |
4 | 22201202320111103 |
5 | 141120323210003 |
6 | 5105150415015 |
7 | 550013125445 |
oct | 124142702523 |
9 | 32145303842 |
10 | 11300210003 |
11 | 4879746035 |
12 | 223450146b |
13 | 10b1199bc4 |
14 | 792ada495 |
15 | 4620e0588 |
hex | 2a18b8553 |
11300210003 has 2 divisors, whose sum is σ = 11300210004. Its totient is φ = 11300210002.
The previous prime is 11300209951. The next prime is 11300210011. The reversal of 11300210003 is 30001200311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11300210003 - 232 = 7005242707 is a prime.
It is a super-2 number, since 2×113002100032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11300210503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650105001 + 5650105002.
It is an arithmetic number, because the mean of its divisors is an integer number (5650105002).
Almost surely, 211300210003 is an apocalyptic number.
11300210003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300210003 is an equidigital number, since it uses as much as digits as its factorization.
11300210003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 11300210003 its reverse (30001200311), we get a palindrome (41301410314).
The spelling of 11300210003 in words is "eleven billion, three hundred million, two hundred ten thousand, three".
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