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1130021041322 = 2565010520661
BaseRepresentation
bin10000011100011010100…
…000001011010010101010
311000000210002221200101002
4100130122200023102222
5122003240341310242
62223042520355002
7144432655240235
oct20343240132252
94000702850332
101130021041322
113a626a466748
12163009915a62
1382739629754
143c99c62c41c
151e5db384432
hex1071a80b4aa

1130021041322 has 4 divisors (see below), whose sum is σ = 1695031561986. Its totient is φ = 565010520660.

The previous prime is 1130021041321. The next prime is 1130021041327. The reversal of 1130021041322 is 2231401200311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1059003588241 + 71017453081 = 1029079^2 + 266491^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1130021041294 and 1130021041303.

It is not an unprimeable number, because it can be changed into a prime (1130021041321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282505260329 + ... + 282505260332.

Almost surely, 21130021041322 is an apocalyptic number.

1130021041322 is a deficient number, since it is larger than the sum of its proper divisors (565010520664).

1130021041322 is an equidigital number, since it uses as much as digits as its factorization.

1130021041322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565010520663.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1130021041322 its reverse (2231401200311), we get a palindrome (3361422241633).

The spelling of 1130021041322 in words is "one trillion, one hundred thirty billion, twenty-one million, forty-one thousand, three hundred twenty-two".

Divisors: 1 2 565010520661 1130021041322