Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11011000100010001 |
3 | 1002011112100201022011 |
4 | 22201202323010101 |
5 | 141120324034301 |
6 | 5105150542521 |
7 | 550013203213 |
oct | 124142730421 |
9 | 32145321264 |
10 | 11300221201 |
11 | 4879753495 |
12 | 2234507a41 |
13 | 10b11a2029 |
14 | 792b005b3 |
15 | 4620e3a51 |
hex | 2a18bb111 |
11300221201 has 4 divisors (see below), whose sum is σ = 11300491504. Its totient is φ = 11299950900.
The previous prime is 11300221199. The next prime is 11300221267. The reversal of 11300221201 is 10212200311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10212200311 = 73421 ⋅139091.
It is a cyclic number.
It is not a de Polignac number, because 11300221201 - 21 = 11300221199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11300221271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57615 + ... + 160996.
It is an arithmetic number, because the mean of its divisors is an integer number (2825122876).
Almost surely, 211300221201 is an apocalyptic number.
It is an amenable number.
11300221201 is a deficient number, since it is larger than the sum of its proper divisors (270303).
11300221201 is an equidigital number, since it uses as much as digits as its factorization.
11300221201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 270302.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11300221201 its reverse (10212200311), we get a palindrome (21512421512).
The spelling of 11300221201 in words is "eleven billion, three hundred million, two hundred twenty-one thousand, two hundred one".
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