113002212481451 has 2 divisors, whose sum is σ = 113002212481452. Its totient is φ = 113002212481450.

The previous prime is 113002212481447. The next prime is 113002212481453. The reversal of 113002212481451 is 154184212200311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113002212481451 - 2² = 113002212481447 is a prime.

It is a Sophie Germain prime.

Together with 113002212481453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113002212481453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501106240725 + 56501106240726.

It is an arithmetic number, because the mean of its divisors is an integer number (56501106240726).

Almost surely, 2^{113002212481451} is an apocalyptic number.

113002212481451 is a deficient number, since it is larger than the sum of its proper divisors (1).

113002212481451 is an equidigital number, since it uses as much as digits as its factorization.

113002212481451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 35.

Adding to 113002212481451 its reverse (154184212200311), we get a palindrome (267186424681762).

The spelling of 113002212481451 in words is "one hundred thirteen trillion, two billion, two hundred twelve million, four hundred eighty-one thousand, four hundred fifty-one".