Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11101101110110001 |
3 | 1002011112101021021022 |
4 | 22201202331232301 |
5 | 141120324411423 |
6 | 5105151105225 |
7 | 550013250062 |
oct | 124142755661 |
9 | 32145337238 |
10 | 11300232113 |
11 | 4879760705 |
12 | 2234512215 |
13 | 10b11a6ca1 |
14 | 792b04569 |
15 | 4620e6dc8 |
hex | 2a18bdbb1 |
11300232113 has 2 divisors, whose sum is σ = 11300232114. Its totient is φ = 11300232112.
The previous prime is 11300232107. The next prime is 11300232149. The reversal of 11300232113 is 31123200311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7602619249 + 3697612864 = 87193^2 + 60808^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11300232113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11300232091 and 11300232100.
It is not a weakly prime, because it can be changed into another prime (11300232913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650116056 + 5650116057.
It is an arithmetic number, because the mean of its divisors is an integer number (5650116057).
Almost surely, 211300232113 is an apocalyptic number.
It is an amenable number.
11300232113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300232113 is an equidigital number, since it uses as much as digits as its factorization.
11300232113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11300232113 its reverse (31123200311), we get a palindrome (42423432424).
The spelling of 11300232113 in words is "eleven billion, three hundred million, two hundred thirty-two thousand, one hundred thirteen".
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