Base | Representation |
---|---|
bin | 1010010001110000101100… |
… | …0111010111110010100001 |
3 | 1111000021220112102020011001 |
4 | 2210130023013113302201 |
5 | 2440120400313000401 |
6 | 40011132221152001 |
7 | 2244262421246341 |
oct | 244341307276241 |
9 | 44007815366131 |
10 | 11300245437601 |
11 | 3667452a530aa |
12 | 13260913bb601 |
13 | 63c7bb0587c3 |
14 | 2b0d13126d21 |
15 | 148e2a69a601 |
hex | a470b1d7ca1 |
11300245437601 has 8 divisors (see below), whose sum is σ = 11331747620864. Its totient is φ = 11268747120960.
The previous prime is 11300245437557. The next prime is 11300245437617. The reversal of 11300245437601 is 10673454200311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11300245437601 - 231 = 11298097953953 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11300245432601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4936681 + ... + 6853561.
It is an arithmetic number, because the mean of its divisors is an integer number (1416468452608).
Almost surely, 211300245437601 is an apocalyptic number.
It is an amenable number.
11300245437601 is a deficient number, since it is larger than the sum of its proper divisors (31502183263).
11300245437601 is a wasteful number, since it uses less digits than its factorization.
11300245437601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1933311.
The product of its (nonzero) digits is 60480, while the sum is 37.
Adding to 11300245437601 its reverse (10673454200311), we get a palindrome (21973699637912).
The spelling of 11300245437601 in words is "eleven trillion, three hundred billion, two hundred forty-five million, four hundred thirty-seven thousand, six hundred one".
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