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1130031212113 = 23471045357273
BaseRepresentation
bin10000011100011011000…
…110111110011001010001
311000000210211002102002001
4100130123012332121101
5122003300442241423
62223043522354001
7144433140550546
oct20343306763121
94000724072061
101130031212113
113a6275183161
121630111bb901
138273b77ac7b
143c99db18bcd
151e5dc1e2cad
hex1071b1be651

1130031212113 has 8 divisors (see below), whose sum is σ = 1204251579648. Its totient is φ = 1057901559264.

The previous prime is 1130031212081. The next prime is 1130031212137. The reversal of 1130031212113 is 3112121300311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1130031212113 - 25 = 1130031212081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130031212813) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 522677556 + ... + 522679717.

It is an arithmetic number, because the mean of its divisors is an integer number (150531447456).

Almost surely, 21130031212113 is an apocalyptic number.

It is an amenable number.

1130031212113 is a deficient number, since it is larger than the sum of its proper divisors (74220367535).

1130031212113 is a wasteful number, since it uses less digits than its factorization.

1130031212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1045357343.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1130031212113 its reverse (3112121300311), we get a palindrome (4242152512424).

The spelling of 1130031212113 in words is "one trillion, one hundred thirty billion, thirty-one million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 23 47 1081 1045357273 24043217279 49131791831 1130031212113