Base | Representation |
---|---|
bin | 10101000011000110… |
… | …10001010011101100 |
3 | 1002011112112100021012 |
4 | 22201203101103230 |
5 | 141120334443200 |
6 | 5105152524352 |
7 | 550014032624 |
oct | 124143212354 |
9 | 32145470235 |
10 | 11300312300 |
11 | 4879805982 |
12 | 22345506b8 |
13 | 10b1204634 |
14 | 792b25884 |
15 | 462110a35 |
hex | 2a18d14ec |
11300312300 has 18 divisors (see below), whose sum is σ = 24521677908. Its totient is φ = 4520124880.
The previous prime is 11300312297. The next prime is 11300312351. The reversal of 11300312300 is 321300311.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56501462 + ... + 56501661.
Almost surely, 211300312300 is an apocalyptic number.
11300312300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11300312300 is an abundant number, since it is smaller than the sum of its proper divisors (13221365608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11300312300 is a wasteful number, since it uses less digits than its factorization.
11300312300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113003137 (or 113003130 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 11300312300 its reverse (321300311), we get a palindrome (11621612611).
The spelling of 11300312300 in words is "eleven billion, three hundred million, three hundred twelve thousand, three hundred".
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