Search a number
-
+
113003321131 is a prime number
BaseRepresentation
bin110100100111110000…
…1011101011100101011
3101210200101200111110001
41221033201131130223
53322412322234011
6123525113203431
711110220244511
oct1511741353453
9353611614401
10113003321131
1143a19479798
1219a98700577
13a86b7a4cbc
1456800124b1
152e15ae57c1
hex1a4f85d72b

113003321131 has 2 divisors, whose sum is σ = 113003321132. Its totient is φ = 113003321130.

The previous prime is 113003321129. The next prime is 113003321141. The reversal of 113003321131 is 131123300311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113003321131 - 21 = 113003321129 is a prime.

It is a super-2 number, since 2×1130033211312 (a number of 23 digits) contains 22 as substring.

Together with 113003321129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 113003321099 and 113003321108.

It is not a weakly prime, because it can be changed into another prime (113003321141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56501660565 + 56501660566.

It is an arithmetic number, because the mean of its divisors is an integer number (56501660566).

Almost surely, 2113003321131 is an apocalyptic number.

113003321131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113003321131 is an equidigital number, since it uses as much as digits as its factorization.

113003321131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 113003321131 its reverse (131123300311), we get a palindrome (244126621442).

The spelling of 113003321131 in words is "one hundred thirteen billion, three million, three hundred twenty-one thousand, one hundred thirty-one".