11300413431433 has 32 divisors (see below), whose sum is σ = 13713502466304. Its totient is φ = 9090289508352.

The previous prime is 11300413431427. The next prime is 11300413431451. The reversal of 11300413431433 is 33413431400311.

It is a happy number.

It is not a de Polignac number, because 11300413431433 - 2²⁵ = 11300379877001 is a prime.

It is a super-2 number, since 2×11300413431433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11300413431395 and 11300413431404.

It is not an unprimeable number, because it can be changed into a prime (11300413431133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 89397591 + ... + 89523907.

It is an arithmetic number, because the mean of its divisors is an integer number (428546952072).

Almost surely, 2^{11300413431433} is an apocalyptic number.

It is an amenable number.

11300413431433 is a deficient number, since it is larger than the sum of its proper divisors (2413089034871).

11300413431433 is a wasteful number, since it uses less digits than its factorization.

11300413431433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128481.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 11300413431433 its reverse (33413431400311), we get a palindrome (44713844831744).

The spelling of 11300413431433 in words is "eleven trillion, three hundred billion, four hundred thirteen million, four hundred thirty-one thousand, four hundred thirty-three".