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11300415003421 is a prime number
BaseRepresentation
bin1010010001110001010100…
…1110001101101100011101
31111000022100100111001201121
42210130111032031230131
52440121222220102141
640011201115410541
72244266550446335
oct244342516155435
944008310431647
1011300415003421
11366752a739445
12132611a153a51
1363c8172182cb
142b0d2b8660c5
15148e3a4e21d1
hexa471538db1d

11300415003421 has 2 divisors, whose sum is σ = 11300415003422. Its totient is φ = 11300415003420.

The previous prime is 11300415003359. The next prime is 11300415003443. The reversal of 11300415003421 is 12430051400311.

11300415003421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9674675251396 + 1625739752025 = 3110414^2 + 1275045^2 .

It is a cyclic number.

It is not a de Polignac number, because 11300415003421 - 211 = 11300415001373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11300415009421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650207501710 + 5650207501711.

It is an arithmetic number, because the mean of its divisors is an integer number (5650207501711).

Almost surely, 211300415003421 is an apocalyptic number.

It is an amenable number.

11300415003421 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300415003421 is an equidigital number, since it uses as much as digits as its factorization.

11300415003421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11300415003421 its reverse (12430051400311), we get a palindrome (23730466403732).

The spelling of 11300415003421 in words is "eleven trillion, three hundred billion, four hundred fifteen million, three thousand, four hundred twenty-one".