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11300952596653 is a prime number
BaseRepresentation
bin1010010001110011010101…
…0000111110000010101101
31111000100201211001122000001
42210130311100332002231
52440123322331043103
640011330322104301
72244316066065466
oct244346520760255
944010654048001
1011300952596653
113667786142175
12132624a1ab091
1363c8a1703605
142b0d7d005d6d
15148e6c7d401d
hexa473543e0ad

11300952596653 has 2 divisors, whose sum is σ = 11300952596654. Its totient is φ = 11300952596652.

The previous prime is 11300952596621. The next prime is 11300952596677. The reversal of 11300952596653 is 35669525900311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10071876598884 + 1229075997769 = 3173622^2 + 1108637^2 .

It is a cyclic number.

It is not a de Polignac number, because 11300952596653 - 25 = 11300952596621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11300952596594 and 11300952596603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11300952596603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650476298326 + 5650476298327.

It is an arithmetic number, because the mean of its divisors is an integer number (5650476298327).

Almost surely, 211300952596653 is an apocalyptic number.

It is an amenable number.

11300952596653 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300952596653 is an equidigital number, since it uses as much as digits as its factorization.

11300952596653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6561000, while the sum is 55.

The spelling of 11300952596653 in words is "eleven trillion, three hundred billion, nine hundred fifty-two million, five hundred ninety-six thousand, six hundred fifty-three".