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11301003412513 is a prime number
BaseRepresentation
bin1010010001110011100001…
…0010110100010000100001
31111000100212100200100020221
42210130320102310100201
52440123423333200023
640011335335203041
72244320254031623
oct244347022642041
944010770610227
1011301003412513
11366780189a951
121326263216481
1363c8ac0b6179
142b0d85a72c13
15148e71ec085d
hexa47384b4421

11301003412513 has 2 divisors, whose sum is σ = 11301003412514. Its totient is φ = 11301003412512.

The previous prime is 11301003412483. The next prime is 11301003412639. The reversal of 11301003412513 is 31521430010311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11047599906849 + 253403505664 = 3323793^2 + 503392^2 .

It is an emirp because it is prime and its reverse (31521430010311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11301003412513 - 237 = 11163564459041 is a prime.

It is not a weakly prime, because it can be changed into another prime (11301003412313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650501706256 + 5650501706257.

It is an arithmetic number, because the mean of its divisors is an integer number (5650501706257).

Almost surely, 211301003412513 is an apocalyptic number.

It is an amenable number.

11301003412513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11301003412513 is an equidigital number, since it uses as much as digits as its factorization.

11301003412513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 11301003412513 its reverse (31521430010311), we get a palindrome (42822433422824).

The spelling of 11301003412513 in words is "eleven trillion, three hundred one billion, three million, four hundred twelve thousand, five hundred thirteen".